Question

1. One side of a square is increased by 2 metres and the other side is reduced by 2 metres. Then a rectangle is formed whose perimeter is 48cm. Find the side of the original square.

Answer 1

Answer:

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Answer 2

Let the sides of the square be X

Then the sides of the rectangle be

X-2 and X+2 (from the question)

Given perimerer of rectangle is 48m

We know that the formula to find the perimeter of rectangle is

2( l+b ) = 48

Therefore,

2(X-2 + X+2) = 48

2( 2X ) = 48

( 2X ) = 48/2

X = 24/2

X = 12

Therefore length of sides of square is 12m.

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