Math, asked by krrishsinghrajput26, 8 months ago

1) one tap can fill a cistern in 3hours and the waste pipe can empty the full cistern in 5hours. In what time will the empty cistern be full, if the tap and the waste pipe are kept open together?​

Answers

Answered by nath12849
2

Answer:

One tap can fill a cistern in = 3 hours

Waste pipe can empty a cistern in = 5 hours

∴ One tap 1 hour work = 1/3

Waste pipe 1 hour work = 1/5

∴ One tap and waste pipe together 1 hour work

= 1/3 – 1/5 = (5 – 3)/15

= 2/15

∴ Empty cistern will be full in 15/2 hours

= 7. ½ hours

Step-by-step explanation:

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