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one zero of the quadratic polynomial (K-1) x ² + Kx + 1 is -3
find value of k
Answers
Answered by
2
- x= -3
- (k -1)x²+kx+1= 0
- (k-1)(-3)²+k(-3)+1=0
- (k-1)(9)-3k+1=0
- 9k-9-3k+1=0
- 9k-3k-9+1=0
- 6k-8=0
- 6k=8
- k=8/6
- k=4/3.
hope this will help you to understand
Answered by
0
f(x) = (K-1) x ² + Kx + 1
f(3) = 0
(K-1) (-3 )² + K(-3 )+ 1 = 0
9(k-1)-3k+1= 0
9k-9-3k+1= 0
6k-8 =0
k= 8/6
k= 4/3
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