1.Out of the following equations which equation has 3 as a solution? (A) x^(2)-x-6=0 (B) x^(2)+x-6=0 (C) x^(2)-x+6=0 (D) x^(2)+x+6=0
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Answer:
1)x^2-x-6
=(3)^2-(3)-6[if we substitute "3" in place of x we get zero . therefore 3 is the root of the equation.]
=9-3-6
=9-9
=0
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