Question

1 )Out of two similar triangles, sides of the smaller triangles are 5,6,7. If the perimeter of the larger triangle is 108, then find the lengths of the sides of the larger triangle.​

Answer 1

Answer:

42 units

Step-by-step explanation:

let the side of the triangle be 5x,6x,7x

so the equation so formed is 5x+6x+7x=108 units

18x= 108

x=108÷18

x=6

so, the longest side 7x= 7×6= 42 units

Answer 2

Given,

The edge of the small triangle = 5, 6, 7cm.

The large triangle's perimeter = 108cm.

To Find,

The edges of the large triangle.

Solution,

Given that,

Both are similar triangles.

5, 6, and 7 are the edges of the small triangle.

108cm is the perimeter of another triangle.

Let's assume,

edges of large triangle = 5x, 6x, 7x.

5x + 6x +7x = 108cm

18x = 108

x = 108 / 18

x = 6

Apply value of x.

5x = 5*6

30cm

6x = 6*6

36cm

7x = 7*6

42cm

Hence, the larger triangle has edges of 30, 36, and 42cm.