Question

1. Oxygen can be prepared from hydrogen peroxide in the presence of a catalyst only (a) (i) Name the catalyst -----------------------------------------------------
(ii) Write an equation for the reaction -----------------------------------------------------
(b)Burning magnesium was lowered into a jar containing oxygen
(i) State what was observed -----
(ii) Write an equation for the reaction -----
(iii) State the type of change it undergoes----

PLEASE ANSWER I WILL MARK AS BRAINLIEST

Answer 1

Explanation:

Question 3.

Give the steps you will use to separate the variables and then solve the equation:

(a) 3n – 2 = 46

(b) 5m + 7 = 17

(c) 20p3=40

(d) 3p10=6 hi oh vo if go in vi if go if

Solution:

(a) 3n – 2 = 46

⇒ 3n- 2 + 2 = 46+ 2 (adding 2 to both sides)

⇒ 3n = 48

⇒ 3n + 3 = 48 ÷ 3

Answer 2

Answer:

a) manganese(IV) oxide

 ii) Because it is neither a reactant nor a product, a catalyst is shown in a chemical equation by being written above the yield arrow. A catalyst works by changing the specific way in which the reaction occurs, called its mechanism.

Explanation:

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