Question

1
P(1) =
1 +15(2.1)
Where where P(t) is the proportion of the population that has the virus (t) days
after the acquisition of virus started. Find p(4) and p(10), and interpret the results.​

Answer 1

Explanation:

P (4) = 4 + 15 (2.4)

= 124

P (10)= 10 + 15(2.10)

= 310

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Answer 2

p(4) = 0.139 and p(10) = 0.377

Given:

p(t) is a population proportion that has the virus(t) days the acquisition of virus started

To Find:

p(4) and p(10) to get the answer in decimals

Solution:

Substituting p(4) to,

p(t) = $\frac{1}{1+15(2.1)^{-0.3t\\} }$

p(4)  = $\frac{1}{1+15(2.1)^{-0.3(4)\\\\} }$

p(4) =  $\frac{1}{1+15(2.1)^{-1.2\\\\} }$

p(4) = $\frac{1}{1+6.15} \\\frac{1}{7.15}$

p(4) = 0.139

Substituting p(10) to,

p(t) = $\frac{1}{1+15(2.1)^{-0.3t\\} }$

p(10) = $\frac{1}{1+15(2.1)^{-0.3(10)\\} }$

p(10) = $\frac{1}{1+15(2.1)^{-3\\} }$

p(10) = 0.377

Hence,

p(4) = 0.139 ,p(10) = 0.377

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