Question

1 p
6. If (a,1), (6.b), (7,5) and
(3.2) taken in order are the
vertices of a parallelogram
then 3a+b is​

Answer 1

Step-by-step explanation:

Given If (a,1), (6.b), (7,5) and  (3.2) taken in order are the  vertices of a parallelogram  then 3a+b is

• Now we have the vertices of a parallelogram. Let P (X,Y) be the midpoint of the diagonals. So they are A(a,1), B(6,b),C(7,5) and D(3,2). Now the diagonals of a parallelogram bisect each other, the co ordinates are  
•     X = 7 + a / 2 = 6 + 3 / 2
•     Or 7 + a = 6 + 3
•     Or 7 + a = 9
•     Or a = 2
• Also Y = 2 + b / 2 = 5 + 1 / 2
•      So 2 + b = 5 + 1
•      Or 2 + b = 6
•      Or b = 6 – 2
•      Or b = 4
• So we have a = 2 and b = 4, so 3a + b = 3(2) + 4
•                                                               = 6 + 4
•                                                                = 10

Reference link will be

https://brainly.in/question/17984434

Answer 2

Answer:

10will be the correct answer hope it helps you