Question

1. p(x)=4x^3+3x^2-4x-3 , g(x)is x-1
2. p(x) x^3+3x^2+5x+6 , g(x)is x+2​

Answer 1

Answer: p(x) = 4x3 – 3x2 + 2x – 4   …(i)

Put  x = 4 in equation (i), we get

p(4) = 4(4)3 – 3(4)2 + 2(4) – 4

= 4 × 64 – 3 × 16 + 8 – 4

= 256 – 48 + 8 – 4

= 264 – 52 = 212

Hence, the remainder is 212.

Step-by-step explanation:Here is your answer

x³-3x²+5x-3 ÷ x²-2

q(x)=x-3

&

r(x) = 7x-9

Answer 2

Step-by-step explanation:

Answer is r(x)=0 in 1st problem and second problem