Question

1. p (x)= (x-1) + (x+1)
2. p (y)= (x+1) - (x-1)
3. p(z) = 4-2power 3- 32power2+224​

Answer 1

1) p(x) = (x − 1) (x + 1)

p(x) = (x − 1) (x + 1)p(0) = (0 − 1) (0 + 1)

p(x) = (x − 1) (x + 1)p(0) = (0 − 1) (0 + 1) = (− 1) (1)

p(x) = (x − 1) (x + 1)p(0) = (0 − 1) (0 + 1) = (− 1) (1) = − 1

Answer 2

$\sf\orange{Answer:1}$

$\sf{p(x)=(x−1)(x+1)}$

$\sf{↛ x {}^{2} −x + x − 1}$

$\sf⇒x {}^{2} − 1$