Question

(1) p(x) = x² +2√2x -6 find the zeros​

Answer 1

Answer:

i hope this will help you

Answer 2

Answer:

${x}^{2} + 2 \sqrt{2} x - 6 = 0 \\ {x}^{2} + 3 \sqrt{2} x - \sqrt{2} x - 6 = 0 \\ x(x + 3 \sqrt{2} ) - \sqrt{2} (x + 3 \sqrt{2} ) = 0 \\ (x + 3 \sqrt{2} )(x - \sqrt{2} ) = 0 \\ x + 3 \sqrt{2} = 0 \: \: \: \: or \: x = - 3 \sqrt{2} \\ x - \sqrt{2} = 0 \: \: \: \: \: or \: x = \sqrt{2}$