Question

1) P(x) = x² – 3x + 2 find p (0) p(0)and p(2) for each of the following polynominals​

Answer 1

(i) p(y)=y

2

−y+1

p(0)=(0)

2

−(0)+1=0+0+1=1

p(1)=(1)

2

−(1)+1=1−1+1=1

p(2)=(2)

2

−(2)+1=4−2+1=3

(ii) p(t)=2+t+2t

2

−t

3

p(0)=2+(0)+2(0)

2

−t

3

=2+0+0−0=2

p(1)=2+(1)+2(2)

2

−(1)

3

=2+1+2−1=4

p(2)=2+(2)+2(2)

2

−(2)

3

=2+2+8−8=4.

(ii) p(t)=2+t+2t

2

−t

3

p(0)=2+(0)+2(0)

2

−t

3

=2+0+0−0=2

p(1)=2+(1)+2(2)

2

−(1)

3

=2+1+2−1=4

p(2)=2+(2)+2(2)

2

−(2)

3

=2+2+8−8=4

Answer 2

Step-by-step explanation:

p(0)=2

p(2)=0

substitute the values 0 and 2 in above equation