Math, asked by akshayakorsa, 6 months ago

1) P(x) = x² - 5X-6, find the values o
P(1), P(2), P(3), P(0), P(-1),
P(-2), P (-3)

Answers

Answered by sahithi9910
2

Step-by-step explanation:

p(x)=x²-5x-6

p(1)=(1)²-5×1-6

=1-5-6

=1-11=-10

p(2)=2²-5×2-6

=4-10-6

=4-16

=-12

p(3)=3²-5×3-6

=9-15-6

=9-21 = -12

p(0)=0²-5×0-6

=-6

p(-1)= (-1)²-5×-1-6

= 1+5-6

= 0

p(-2)=(-2)²-5×-2 -6

=4+10-6

=14-6 = 8

p(-3)=(-3)²-5×-3-6

=9+15-6

=24-6 =18

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