Question

1) p(x)=x²-5x-6,find values of p(1),p(2),p(3),p(0),p(-1),p(-2),p(-3)​

Answer 1

Answer:

Given:

p(x)=x²-5x-6

p(1)=(1)²-5(1)-6

=1-5-6

= -10

p(2)= (2)²-5(2)-6

= 4-10-6

= -12

p(3)= (3)²-5(3)-6

= 9-15-6

= -12

p(0)=(0)²-5(0)-6

= 0-0-6

= -6

p(-1)= (-1)²-5(-1)-6

= 1+5-6

=0

p(-2)=(-2)²-5(-2)-6

= 4+10-6

= 8

p(-3)= (-3)²-5(-3)-6

= 9+15-6

=18