Math, asked by swapnakalidas5, 1 month ago

1) p²q-pr²-pq+r² 2) 6ab-b² +12ac-2bc​

Answers

Answered by kakasahebpawar4579
0

Answer:

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Answered by bhavyaupputuri6
1

Answer:

1) (p-1),(pq-r^2)

Step-by-step explanation:

p^2q-pr^2-pq+r^2

it can be written as p(pq-r^2)-1(pq-r^2)=(p-1) (pq-r^2)

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