Question

1. प्रकाशिकी (या प्रकाश-विज्ञान) में प्रयुक्त चिन्ह परिपाटी लिखिए।​

Answer 1

Answer:

Given:

Magnitude of two forces F₁ = 3N

and F₂ = 4N

Angle between F₁ and F₂ = θ = 90°

To find:

Resultant of two forces.

Solution:

Resultant force :-

$\sf{\implies \sqrt{ {{F}^{2}}_{1} + {{F}^{2}}_{2} + 2{F}_{1} {F}_{2} \cos \theta}}$

We know that cosθ = 0⠀⠀⠀⠀⠀

So, R =

$\sf{\implies \sqrt{ {{F}^{2}}_{1} + {{F}^{2}}_{2}}$

$\sf{\implies R = \sqrt{{3}^{2} + {4}^{2}} }$

$\sf{\implies R = \sqrt{9+16}}$

$\sf{\implies R = \sqrt{25}}$

$\sf{\implies R = 5 \: N}$

Hence magnitude of the resultant force is 5N.