Math, asked by shivamyadav72, 1 year ago

1. प्रत्येक अनुक्रम के पाँच पद लिखिए तथा संगत श्रेणी ज्ञात कीजिए
(a) a1 = 3, a = 3an-1+ 2 सभी n 21 के लिए
(b) a1 = - 1, an = , जहाँ n>2
(c) 41 = a2 = 2, an = an-1-1 जहाँ n>2
an-1, जहाँ
n​

Answers

Answered by amitnrw
3

Answer:

Step-by-step explanation:

a)

a₁ = 3 aₙ = 3aₙ₋₁ + 2

a₂ =  3*a₁ + 2 = 3 * 3 + 2 = 11

a₃ = 3a₂ + 2 = 3 * 11 + 2 = 35

a₄ = 3*a₃ + 2  = 3 * 35 + 2 = 107

a₅ = 3*a₄ +2 = 3 * 107 + 2 = 323

b)

a₁ = - 1   aₙ = aₙ₋₁ /n   n≥ 2

a₂ =  a₁/2 = -1/2

a₃ = a₂/3  =  -1/6

a₄ = a₃/4 = -1/24

a₅ = a₄/5 = - 1/120

c)

a₁ = a₂ = 2   & aₙ = aₙ₋₁ - 1

a₃ = a₂ - 1  = 2 - 1 = 1

a₄ = a₃ - 1 = 1 - 1 = 0

a₅ = a₄ - 1 = 0 - 1 = -1

a₆ = a₅ - 1 = - 1 - 1 = -2

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