Question

1.particle of mass 5 g is moving with a linear velocity 5m/s in a circular path of radius 10 cm ,then its

centripetal force will be

A. 1.25N. B. 12.5 N. C. 125N. D. none of these
2. ​

Answer 1

Answer:

OPTION B

Explanation:

           Fc=mv^2/r

               =5 x 25 /10

                =125/10

                =12.5N

Answer 2

Given:

A particle of mass 5 g is moving with a linear velocity of 5m/s in a circular path of radius 10 cm.

To find:

Value of centripetal force ?

Calculation:

• Centripetal force is a force vector experienced by an object in a circular trajectory. The vector is oriented radially inwards (i.e. towards centre).

The general expression of centripetal force :

$\therefore \: F_{c} = \dfrac{m {v}^{2} }{r}$

$\implies \: F_{c} = \dfrac{ \dfrac{5}{1000} \times {5}^{2} }{ \dfrac{10}{1000} }$

$\implies \: F_{c} = \dfrac{ 5\times {5}^{2} }{10}$

$\implies \: F_{c} = \dfrac{125}{10}$

$\implies \: F_{c} = 12.5 \: N$

So, centripetal force is 12.5 N (Option B).