Question

1) Particle's velocity changes form (2î + 3ſ) m/s to (2î - 31) m/s in
2s. The acceleration in m/s? is
a) –î + 5ſ) b) (î + 5ſ)/2
c) zero
d) (-3j^)
​

Answer 1

Answer:

d) (-3Ĵ)

Explanation:

Given :

Particle's velocity changes form (2î + 3Ĵ) m/s to (2î - 3Ĵ) m/s in

2s. Find the acceleration,.

Solution :

We know that,

$Acceleration = \frac{change \  in \ velocity}{change \  in \ time}$

⇒ $\frac{\Delta v}{\Delta t} = \frac{v_2 - v_1}{\Delta t}$

⇒ $\frac{(2i - 3j) - (2i + 3j)}{2}$

⇒ $\frac{2i - 3j - 2i - 3j}{2}$

⇒ $\frac{-6j}{2} = -3j$