Question

1 pc
Q18. If the system of equations kx-y=2 and 6x-2y=3 has unique
solution then k is not equal to
а.
3
b. о с. -3
с. -3 d.1
О O
а
О O
b​

Answer 1

Answer:

6x−2y=3,kx−y=2

y=kx−2

6x−2(kx−2)=3

6x−2kx+4=3

x(6−2k)=−1

x=

6−2k

−1

k=3 Since denominator

hope this will help you.....