Question

1 pd
For the given cell, Mg Mg2+ | Cu2+ Cu
(A) Mg is cathode
(C) The cell reaction is Mg + Cu2+ →Mg2+ + Cu
(B) Buis cathode
(D) Cu is the oxidizing agent​

Answer 1

Given:

A cell is given consisting of two ions as follows:

$\boxed{ \rm{Mg : {Mg}^{ + 2} \: | \: {Cu}^{ + 2} : Cu}}$

To find:

The correct statement/s :

(A) Mg is cathode

(B) The cell reaction is Mg + Cu2+ →Mg2+ + Cu

(C) Cu is cathode

(D) Cu is the oxidizing agent

Solution:

$\sf{Mg \rightarrow {Mg}^{ + 2} + 2e} \\ \sf{{Cu}^{ + 2} + 2e \rightarrow Cu}$

So, cell reaction becomes:

$\boxed{ \red{ \large{ \sf{Mg + {Cu}^{ + 2} \rightarrow{Mg}^{ + 2} + Cu} }}}$

Here , Copper (Cu+2) acts as the oxidising agent.

Copper(Cu) is the cathode.

So, statements 2 , 3 and 4 are correct.