1 pH of a buffer solution having 0.01 M CH3COONa and 0.1 M CH3COOH (pKa = 4.74) is
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Answer:
So here is your answer
Explanation:
Ph= 7+1/2(pKa+logC)
= 7+1/2(4.7+log10^-2)
= 7+2.35-1
=8.35
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