Question

1 physics gravitation - derivation of acceleration due to gravity

Answer 1

To calculate the value of 'g' (acceleration due to gravity).

Take the values as,

G = 6.7$\times$ $10^{-11}Nm^2kg$

Mass of Earth = $6 \times 10^{24} kg$

Radius of Earth = $6.4 \times 10^6m$

g = $\frac{GM}{R^2}$

g = $\frac{6.7 \times 10^{-11} \times 6 \times 10^{24}}{(6.4 \times 10^6)^2}$

g = $\frac{6.7 \times 6 \times 10^{(-11+24)}}{6.4 \times 6.4 \times 10^{12}}$

g = $\frac{6.7 \times 6 \times 10^{(-11+24-12)}}{6.4 \times 6.4}$

g = $\frac{6.7 \times6 \times 10^1}{6.4 \times 6.4}$

g = $\frac{6.7 \times 6 \times 10}{6.4 \times 6.4}$

g = $\frac{67 \times 6}{6.4 \times 6.4}$

g = $\frac{67 \times 3}{3.2 \times 6.4}$

g = $\frac{201}{20.48}$

g = $\frac{20100}{2048}$

g = $9.8m/s^2$

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