Question

1) Pipe A can fill a tank in 3 hours. Pipe B can fill it
in 4 hours. An outlet pipe C can empty the full
tank in 6 hours. If all three pipes are kept open
simultaneously, in how many hours will the tank
be half full? ​

Answer 1

Answer:

Pipe A fill in = 1/3 hour

Pipe B fill in = 1/4 hour

pipe C empty in = 1/6 hour

if opened simuntaneously =

1/3 + 1/4 - 1/6

5/12

Step-by-step explanation:

Answer 2

Answer:

5/12

Step-by-step explanation:

Pipe A fill in = 1/3 hour

Pipe B fill in = 1/4 hour

Pipe C empty in = 1/6 hour

The pipes are opened simultaneously =

1/3 + 1/4 - 1/6  = 5/12