Question

1. Pipe A can fill an empty tank in 6 hours and pipe B in 8 hours if both the pipe
are opened and after 2 hours pipe A is closed, how much time B
remaining tank? HOTS
please bta do koi​

Answer 1

Step-by-step explanation:

let that pipe A fill complete tank 'x' in 6 hours

therefore in 2 hours it can fill 2x/6=x/3

also B can fill complete tank 'x' in 10 hours

therefore in 2 hours it can fill =x/5

the remaining tank =x-x/3-x/5=7x/15

as A pipe is closed

so the pipe b can fill remaining pipe in 7/150 hours

SIMPLY APPLY UNITARY METHOD