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plz friends help me with this question i dont know to solve it . answer the fifth question in the pdf file plz
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In triangle ABD and ADC
Angle ADC=Angle ADB=90 degree
AB=AC.....(given)
AD=AD.......(Common)
Triangle ABD is congurent to triangle ADC (By R.H.S axiom of congurency)
BD=DC(By C.P.CT)
Hence AD bisects BC
Angle BAD=Angle DAC (by C.P.C.T)
AD bisects Angle A
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