Question

1 point
1) A body of mass 1 kg is
moving in a vertical circular
path of radius 1 m. The
difference between the kinetic
energy at it's highest and
lowest position is--- (1 mark)
O A) 10 J
O B) 20 J
O C) 4 v5 J
O D) 10 % (V5-1) J​

Answer 1

Answer:

b.) tho We can't solve it without the velocity

Answer 2

Answer-B-20J

Explanation:

Radius of the circle, r = 1 m. So the highest point circular path, h = 2 m. K.E = 19. ... Thus, the difference between the k.E at its highest and lowest point is 19