Question

1 point
14) If -2 and 3 are the zeroes of the quadratic
polynomial x² + (a + 1)x + b then
a) a= -2, b= 6 c) a = 2, b = -6
b) a = -2, b = -6 d) a = 2, b=6​

Answer 1

Answer:

b) a = -2 , b = -6

Step-by-step explanation:

By Comparing (x² + (a + 1)x + b) by Ax^2 + Bx + C

We Get

A = 1

B = (a+1)

C = b

Let α be -2 and β be 3

α + β = -B/A

- 2 + 3 = - (a+1)/1

        1 = - a -1

        a = -2

α * β = C/A

(-2)(3) = b/1

     -6 = b