1 point 16) Total current in the following circuit is 322 5Ω con 622 I 14V O (A) 2 A O (B)1 A O (C) 2.5 A O (D) 4A
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Answer:
From Ohm's law
V=IR
V=622114v
R=3225 ohm
here, V=IR
V/R=I
I=V/R
I=622114/3225
I=?
But,there's already given total current
which is 16A
Current through given resistor
total current / given resistor=16/3225=4A
hence option D
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