Question

1 point
19. The allowable combinations of quantum numbers for each of the electron is 4s.
3p. 5d orbitals respectively
1) n = 4.1= 0, m, = 11; n = 3,1 = 2, m = 1. n = 5, 1 = 3. m, = 0
2) n = 4,1 = 0, m = 0; n = 3, 1 = 0, m, = 9; n = 5. I = 1, m, = 0
3) n = 4.1 = 0. m = 0: n = 3. I = 2. m = -1; n = 5.1 = 3. m, = -2
4) n = 4.1 = 0, m = 0; n = 3.1=1, m, = 0; n = 5.1 = 2. m, = -1
O 1
1.
O 2​

Answer 1

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