Question

1 point 2. A stone of mass 310 g falls from a height. How much K.E. will it possess when it acquires a velocity of 5m/s? a 0.775 J
b.0.5 J
c 3.875 J
d.15500 J​

Answer 1

• Mass =310g=0.31kg
• Velocity=5m/s

We know

$\boxed{\sf K.E=\dfrac{1}{2}mv^2}$

• m denotes to mass
• v denotes to velocity

$\\ \sf\longmapsto K.E=\dfrac{1}{2}\times 0.31(5)$

$\\ \sf\longmapsto k.E=\dfrac{1.5}{2}$

$\\ \sf\longmapsto K.E=0.775J$