Question

1 point
24. In the given figure, if the
exterior angle is 135° then <P is:
P
1350
R
O 45°
O 50°
O 60°
O 90°​

Answer 1

Answer:

by linear angles

180-135

=45°

PQR=PRQ ......given

45°=45°

by angle sum property of triangle

45+45+P=180°

90+P=180°

P=180°-90°

P=90°