Question

1 point
5. The value of 'k' for
which the roots of the
quadratic equattion 3x^2
+2x + k =0 are real and
equal is: *​

Answer 1

★ Given :

Polynomial : 3x² + 2x + k = 0

Polynomial has real and equal roots so D = 0.

$\rule{200}{2}$

★ To Find :

We have to find the value of k for whuch polynomial has real and equal roots.

$\rule{200}{2}$

★ Solution :

We know that,

$\Large{\implies{\boxed{\boxed{\sf{D = b^2 - 4ac}}}}}$

Where,

• a is 3
• b is 2
• c is k

__________[Put Values]

$\sf{\dashrightarrow 0 = (2)^2 - 4(3)(k)} \\ \\ \sf{\dashrightarrow 4 - 12 k = 0} \\ \\ \sf{\dashrightarrow 4 = 12 k} \\ \\ \sf{\dashrightarrow k = \frac{\cancel{4}}{\cancel{12}}} \\ \\ \sf{\dashrightarrow k = \frac{1}{3}}$

$\Large{\implies{\boxed{\boxed{\sf{k = \frac{1}{3}}}}}}$