Question

1 point
6. The mass of an electron is 9.1 x 10-31 kg and velocity of an electron is 2.2 x
10 ms?, if the uncertainty in its velocity is 0.05 %, the uncertainty in its
position would be
(a)
527.0nm (b) 52.7nm (C)
52.7 pm (d) 527pm​

Answer 1

Explanation:

Δx×m×ΔV=

4π

h

Δx= uncertainty in the position

m=9.1×10

−31

kg= mass of electron

ΔV=300×

100

0.001

=0.003m/s

uncertainty in the velocity

h=6.62×10

−36

Js= Planck's constant

Substitute values in the above formula

Δx×9.1×10

−31

×0.003=

4×3.1416

6.62×10

−34

Δx=1.92×10

−2

m

Hence, the correct option is C