Question

1 point
7. The value of the polynomial
f(x) = x2/9 +x/3+1 at x=3 is *
​

Answer 1

Answer:

P(x)=x²-9

=x²-3²

=(x+3)(x-3)

(x+3)(x-3)=0

x+3=0 x-3=0

x=-3 x=3

So x=3,-3 are zeroes of P(x)=x²-9.

Step-by-step explanation:

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Answer 2

Answer:

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