Question

1 point
9. In a circuit a 33 ohm resistor
carries a current of 2 A. The
voltage across the resistor is​

Answer 1

Answer:

Explanation:

Applying Kirchhoff's second law in closed mesh VR  

6

​  

V ,

           V=I  

6

​  

R  

6

​  

 ,

where I  

6

​  

R  

6

​  

 is the voltage drop across resistor 6 ,which is V  

6

​  

=V ,

now , Applying Kirchhoff's second law in closed mesh VR  

1

​  

R  

2

​  

R  

3

​  

V ,

           V=IR+IR+IR=3IR ,

or         IR=V/3

where IR is the voltage drop across resistor 1,2 and 3  

 therefore voltage drop across resistor 6   ,=V

and voltage drop across resistor 3     ,  =V/3

Answer 2

Answer :

66 Voltage

Explanations:

R=V/I formula

33= V/2

V=33 x 2= 66V