Physics, asked by loveghuman, 10 months ago

1 point
A car starts from rest and attains
velocity of 20 m/s in 20 sec. The
distance travelled in the car during
this period is:
O 100 m
O 200 m
O 300 m
400 m
This is a required question​

Answers

Answered by ahanatarafder06
2

Answer: 200 m

Step-by-step Explanation:

u = 0 m/s

v = 20 m/s

t = 20 s

a = v - u

t

a = 20 - 0

20

a = 20

20

a = 1m/s^2

distance = ut + 1 at^2

2

= 0×20 +1 ×1×20×20

2

= 0 + 200

= 200 m

Answered by parasbhumbak3
0

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