Question

1 point
Article A was sold at 20% profit and Article B was sold at 60% profit. The
selling price of Article B was 150% more than that of Article A. Cost price of
Article B is what percent more than that of Article A?
O 87.5%
O 86.5%
0 23.5%
O None​

Answer 1

Answer: None

Step-by-step explanation:

Given :  Article A was sold at 20% profit

             Article B was sold at 60% profit

             S.P of article B was 150% more than that of Article A

To Find : C.P of Article B is what percent more than that of Article A

Solution :

Let the C.P of Article A be x and C.P of Article B be y

∴ S.P of Article A = x + $\frac{20}{100}x$  = $\frac{6x}{5}$

∴ S.P of Article B = $y + \frac{60}{100}$  = $\frac{8}{5} y$

According to question :

S.P of article B was 150% more than that of Article A

⇒ $\frac{8}{5} y = \frac{150}{100} * \frac{6}{5}x$

⇒ $\frac{8}{5} y = \frac{9}{5} x$

∴ $y = \frac{9}{8}x$

∴ % of C.P of article B more than that of Article A = $\frac{9}{8} * 100 = 112.5%$

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