Question

1 point
Question *
2
Find a and bif x =
and x = -3 are roots of ax² + 7x + b = 0,

Answer 1

• Answer:a≈7/9-b
• b is equal to 12/a

Step-by-step explanation:

ax²+7x+bequals to 0

put the value of x

ax²+7(-3)+b

ax²-21+b equals0

ax²+b equals 21

9a+b eqls21

divide 9 on both sides

9a/9+b eqls 21/9

a+b-b eqls 21/9-b

a eqls 21/9 -b

B

9a+b eqls 21

divide a on both sides

9a/a+b eqls 21/a

+9-9+b eqls 21-9/a

beqls 12/a

9a/9+b eqls 21/9