Question

1 point
Solution contains 85.5 g of sucrose (C12 H22 O11) in 250 cm3. What is the molarity?

Answer 1

Answer:

The molarity of the solution is 1 M.

Explanation:

Given mass of sucrose = 85.5 g

Molar mass of sucrose = (12×12) + (22×1) + (11×16)

                                      = 342 g/mol

Number of moles of sucrose = Given mass ÷ molar mass

                                                = $\frac{85.5}{342}$ = 0.25 moles

Given volume of solution = 250 $cm^{3}$ = 0.25 L

Molarity of the solution = Number of moles of sucrose ÷ volume of solution in litres

=$\frac{0.25}{0.25}$

= 1 M

∴ Molarity of the solution is 1 M.