Question

1 point

The length of the diagonal of a rectangle having sides 9 cm and 12 cm is .​

Answer 1

Given:

The sides of a rectangle are 9 cm and 12 cm

To find:

The diagonal of the rectangle

Something about rectangle

• A rectangle is a quadrilateral.
• The opposite sides are equal and parallel.
• The each interior angle of the rectangle is 90°.
• The two diagonals of the rectangle are equal in length.

Now,

As two sides are given and we have to find diagonal of the rectangle we can user the Phythagoras theorem,

(Base)² + (Perpendicular)² = (Hypotenuse)²

⇒ (9)² + (12)² = (diagonal)²

⇒ 81 + 144 = (diagonal)²

⇒ 225 = (diagonal)²

⇒ √225 = diagonal

⇒ 15 = diagonal

Hence,

The diagonal of the rectangle is 15 cm.

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More Information:

• Perimeter of a rectangle = 2(lb + bh + hl) unit sq.
• Area of a rectangle = l*b unit sq.

[Here, 'l' is the 'length', 'b' is the 'breadth', and 'h' is the 'height' of the rectangle]

Answer 2

Answer:

to find the diagonal of rectangle we must follow the Pythagoras theorem

=>(9)^2+(12)^2= x^2

=> 81+144 = x^2

=> 225= x^2

=> X= √225

=>X= 15

so I think ok this answer is clear to you