Question

1 poit
1) Base of a triangle is 8
and height is 5 .Base of
another triangle is 10 and
height is 6. Find the ratio
of areas of these triangles.​

Answer 1

Step-by-step explanation:

Given :- Let The triangle be ∆ABC and ∆PQR.

In ∆ABC,

Base of ∆ABC is BC = 9cm

Altitude of ∆ABC is AE = 5cm

In ∆PQR,

Base is QR = 10cm

Altitude is PM = 6cm

♦ To Find :- Ratio of Area of ∆ABC and ∆PQR

♦ Solution :-

$$\begin{lgathered}= \frac{area \: \: of \: \: abc}{area \: \: of \: \: pqr} \\ \\ = \frac{ \frac{1}{2} \times ae \times bc }{ \frac{1}{2} \times pm \times qr } \\ \\ = \frac{ \frac{1}{2} \times 5 \times 9 }{ \frac{1}{2} \times 6 \times 10} \\ \\ = \frac{3}{4} \\ \\\end{lgathered}$$

Answer 2

Step-by-step explanation:

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