Question

1 por
Q1.0.5 g of Caco3 was
dissolved in dilute HCL and the
solution was made to one litre
by dilution. 100 ml of this
solution required 44 ml of EDTA
solution, while 50 ml of this
sample required 20 ml of EDTA
solution. Calculate the
hardness of water sample."​

Answer 1

Answer:

1000 ml of std. water = 1 gm of CaCO3 (1000 mg)

hence 1 ml of std.water = 1 mg of CaCO3

it is given for 45 ml of EDTA we get,

45 ml EDTA solution = 50 ml