1 power 11+2 power 11 + 2 power 11+ 3 power 11 + 4 power 11 is divisible by 5
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Answer:
Yes, the resultant is divisible by 5
Step-by-step explanation:
This type of problem can be solved by computing the one's digits of the respective powers.
1¹¹ = one's digit will be 1
2¹¹ = one's digit will be 8
3¹¹ = one's digit will be 7
4¹¹ = one's digit will be 4
since excluding these one's digit, the rest of the number will always be divisible by 5, hence the sum of these powers will be equivalent to a multiple of 5 and the summation of these one's digit.
1¹¹ + 2¹¹ + 3¹¹ + 4¹¹ = 5n + 1 + 8 + 7 + 4
= 5n + 20
= 5( n + 4)
Hence the sum of these powers will be divisible by 5.
chinnu4342:
bro there is any another procedure
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