Science, asked by nishchitharaod, 4 months ago

1 . power of a bulb is given by the formula
a . P = RI
b . P = I + RT
c . P = I2R
d . P = R2t​

Answers

Answered by Anonymous
1

Answer:

In a resistor, it is dissipated as heat, and in a light bulb, it is dissipated as heat and light. P=IV=(VR)V=V2R. P=IV=I2R=V2R. The power supplied from the battery is equal to current times the voltage, P=IV.

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