Question

1. PQR is a triangle, right-angled at P. If PQ = 10 cm
and PR = 24 cm, find QR.


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Answer 1

Step-by-step explanation:

if it is right angle at p so QR will be hypotenuse

we know that for a ryt angle triangle

hyp²= base²+perp²

here perp = PR and and base = 10

so QR²= 10²+24²

QR²= 100+576

QR²= 676

QR= √676= 26cm

Answer 2

Answer:

PQ=10cm ,PR=24cm, QR=?

In right angled triangle PQR,

PQ^2+PR^2=QR^2

24^2+10^2 = QR^2

576+100=QR^2

676=QR^2

QR=26(Square of 676)