Question

1. PQR is a triangle, right angled at P. If PQ = 10 cm and PR = 24 cm, find QR.

Answer 1

Answer:

QR =10 cm

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Step-by-step explanation:

In triangle PQR,

Angle P=90°

Therefore, by pythagoras theorem

${pq}^{2} + {qr}^{2} = {pr }^{2} \\ {10 }^{2} + {qr}^{2} = {24}^{2} \\ 100 + {qr}^{2} = 576 \\ 100 +576 = {qr }^{2} \\ 676 = {qr}^{2} \\ taking \: square \: root \: on \: both \: sides \: \\ qr = 26 \: cm$

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Answer 2

Answer:

ΔPQR.....PQ=10 & PR = 24.....which is given

then we need to find,QR = ?

so, in trange...PR²=PQ²+QR²( formula)

so...to find QR =

QR = √PR²-PQ²

put the value....of PR & PQ

SO, we found....QR = √ 24²-10²

= √576-100 = √476 = 21.8174

Step-by-step explanation: