Question

1. PQR is a triangle, right-angled at P. IfPQ= 10 cm
and PR = 24 cm, find QR​

Answer 1

Answer:

Using pythagoras theorem

$h \: = \sqrt{p {}^{2} } + b {}^{2}$

h = underoot 10^2 + 24^2

h = underoot 676

h = 26 cm

QR = 26 cm

Step-by-step explanation:

Hope it helps you.....

Answer 2

Answer:

Refer to the attachment above. ⬆️

hope it helps!!