Question

1. PQR is a triangle, right-angled at P. IfPQ=10 cm
and PR = 24 cm, find QR.​

Answer 1

$\huge \fbox{\underline \purple{Answer-}}$

Mearsurements :-

• Base = 24 cm
• Height = 10 cm
• Hypotenuse = x cm

Formulae of Hypotenuse :-

${a}^{2} + {b}^{2} = {c}^{2}$

(Where c = hypotenuse)

Lets apply the formulae!

${10}^{2} + {24}^{2} = {c}^{2}$

$100 + 576 = {c}^{2}$

$57600 = {c}^{2}$

$c = \sqrt{57600}$

$c = 240 \: cm$

Hope it helps!

Answer 2

Answer:

Mearsurements :-

Base = 24 cm

Height = 10 cm

Hypotenuse = x cm

Formulae of Hypotenuse :-

{a}^{2} + {b}^{2} = {c}^{2}a

2

+b

2

=c

2

(Where c = hypotenuse)

Lets apply the formulae!

{10}^{2} + {24}^{2} = {c}^{2}10

2

+24

2

=c

2

100 + 576 = {c}^{2}100+576=c

2

57600 = {c}^{2}57600=c

2

c = \sqrt{57600}c=

57600

c = 240 \: cmc=240cm