Question

1.
Practice ser
Radius of circle is 10 cm. There are two chords of length 16 cm What will be the distance of these chords from the centre of the circle
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Answer 1

Given :- Length of the chord AB = 16 cm and radius (r) = 10cm .

To find :- OM

Construction :- Draw a perpendicular OM from centre O such that, it bisects the chord AB.

Proof :- In right angled ∆OMB,

OB² = OM² + BM²

=> 10² = OM² + 8²

=> 100 = OM² + 64

=> OM² = $\sqrt{36}$

=> OM = 36

=> OM = 6 cm

Hence, the distance of the chord from the centre of the circle is 6 cm.

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